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- 171E-5.12 B 5-14 F = _____1____ = _________1_________| 2*π*√(L*C) 6.28*√(2E-6*15E-12)
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 2 microhenrys and C is 15 picofarads?
-
- A. 29.1 kHz
- B. 29.1 MHz
- C. 5.31 MHz
- D. 5.31 kHz
- *
- 172E-5.13 C 5-14 F = 1/6.28*√(5E-6*9E-12) |1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 5 microhenrys and C is 9 picofarads?
-
- A. 23.7 kHz
- B. 3.54 kHz
- C. 23.7 MHz
- D. 3.54 MHz
- *
- 173E-5.14 D 5-14 F = 1/6.28*√(2E-6*30E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 2 microhenrys and C is 30 picofarads?
-
- A. 2.65 kHz
- B. 20.5 kHz
- C. 2.65 MHz
- D. 20.5 MHz
- *
- 174E-5.15 A 5-14 F = 1/6.28*√(15E-6*5E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 15 microhenrys and C is 5 picofarads?
-
- A. 18.4 MHz
- B. 2.12 MHz
- C. 18.4 kHz
- D. 2.12 kHz
- *
- 175E-5.16 B 5-14 F = 1/6.28*√(3E-6*40E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 3 microhenrys and C is 40 picofarads?
-
- A. 1.33 kHz
- B. 14.5 MHz
- C. 1.33 MHz
- D. 14.5 kHz
- *
- 176E-5.17 C 5-14 F = 1/6.28*√(40E-6*6E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 40 microhenrys and C is 6 picofarads?
-
- A. 6.63 MHz
- B. 6.63 kHz
- C. 10.3 MHz
- D. 10.3 kHz
- *
- 177E-5.18 D 5-14 F = 1/6.28*√(10E-6*50E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 10 microhenrys and C is 50 picofarads?
-
- A. 3.18 MHz
- B. 3.18 kHz
- C. 7.12 kHz
- D. 7.12 MHz
- *
- 178E-5.19 A 5-14 F = 1/6.28*√(200E-6*10E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 200 microhenrys and C is 10 picofarads?
-
- A. 3.56 MHz
- B. 7.96 kHz
- C. 3.56 kHz
- D. 7.96 MHz
- *
- 179E-5.20 B 5-14 F = 1/6.28*√(90E-6*100E-12)|1. Multiply L*C 2. Take √ |3. Multiply by 6.28 3. Take 1/X
- What is the resonant frequency of the circuit in Figure 4AE-5-2
- when L is 90 microhenrys and C is 100 picofarads?
-
- A. 1.77 MHz
- B. 1.68 MHz
- C. 1.77 kHz
- D. 1.68 kHz
- *
- 180E-5.21 A 5-20 BW = F/Q, BW = 1.8E6/95|BW = 18.9 kHz
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 1.8 MHz and a Q of 95?
-
- A. 18.9 kHz
- B. 1.89 kHz
- C. 189 Hz
- D. 58.7 kHz
- *
- 181E-5.22 D 5-20 BW = F/Q, BW = 3,600,000/218
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 3.6 MHz and a Q of 218?
-
- A. 58.7 kHz
- B. 606 kHz
- C. 47.3 kHz
- D. 16.5 kHz
- *
- 182E-5.23 C 5-20 BW = F/Q, BW = 7.1E6/150|BW = 47.33 kHz
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 7.1 MHz and a Q of 150?
-
- A. 211 kHz
- B. 16.5 kHz
- C. 47.3 kHz
- D. 21.1 kHz
- *
- 183E-5.24 D 5-20 BW = F/Q, BW = 12,800,000/218
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 12.8 MHz and a Q of 218?
-
- A. 21.1 kHz
- B. 27.9 kHz
- C. 17 kHz
- D. 58.7 kHz
- *
- 184E-5.25 A 5-20 BW = F/Q, BW = 14.25E6/150
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 14.25 MHz and a Q of 150?
-
- A. 95 kHz
- B. 10.5 kHz
- C. 10.5 MHz
- D. 17 kHz
- *
- 185E-5.26 D 5-20 BW = F/Q, BW = 21.15E6/95
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 21.15 MHz and a Q of 95?
-
- A. 4.49 kHz
- B. 44.9 kHz
- C. 22.3 kHz
- D. 222.6 kHz
- *
- 186E-5.27 B 5-20 BW = F/Q, BW = 10.1E6/225
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 10.1 MHz and a Q of 225?
-
- A. 4.49 kHz
- B. 44.9 kHz
- C. 22.3 kHz
- D. 223 kHz
- *
- 187E-5.28 A 5-20 BW = F/Q, BW = 18.1E6/195
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 18.1 MHz and a Q of 195?
-
- A. 92.8 kHz
- B. 10.8 kHz
- C. 22.3 kHz
- D. 44.9 kHz
- *
- 188E-5.29 C 5-20 BW = F/Q, BW = 3.7E6/118
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 3.7 MHz and a Q of 118?
-
- A. 22.3 kHz
- B. 76.2 kHz
- C. 31.4 kHz
- D. 10.8 kHz
- *
- 189E-5.30 D 5-20 BW = F/Q, BW = 14.25E6/187
- What is the half-power bandwidth of a parallel resonant circuit
- which has a resonant frequency of 14.25 MHz and a Q of 187?
-
- A. 22.3 kHz
- B. 10.8 kHz
- C. 13.1 kHz
- D. 76.2 kHz
- *
- 190E-5.31 A 5-19 Xl = 6.28*14.128E6*2.7E-6|Q = R/X, Q=18000/239.55|Q = 75.1
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 14.128 MHz, the inductance is 2.7
- microhenrys and the resistance is 18,000 ohms?
-
- A. 75.1
- B. 7.51
- C. 71.5
- D. 0.013
- *
- 191E-5.32 B 5-19 Xl = 2πFL, Xl=417.2|Q = R/X, Q = 18000/417.2
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 14.128 MHz, the inductance is 4.7
- microhenrys and the resistance is 18,000 ohms?
-
- A. 4.31
- B. 43.1
- C. 13.3
- D. 0.023
- *
- 192E-5.33 C 5-19 Xl = 2πFL, Xl=1319|Q = R/X, Q = 180/1319
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 4.468 MHz, the inductance is 47
- microhenrys and the resistance is 180 ohms?
-
- A. 0.00735
- B. 7.35
- C. 0.136
- D. 13.3
- *
- 193E-5.34 D 5-19 Xl = 2πFL, Xl=312.8|Q = R/X, Q = 10000/312.8
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 14.225 MHz, the inductance is 3.5
- microhenrys and the resistance is 10,000 ohms?
-
- A. 7.35
- B. 0.0319
- C. 71.5
- D. 31.9
- *
- 194E-5.35 D 5-19 Xl = 2πFL, Xl = 367.1|Q = R/X, Q = 1000/367.1
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 7.125 MHz, the inductance is 8.2
- microhenrys and the resistance is 1,000 ohms?
-
- A. 36.8
- B. 0.273
- C. 0.368
- D. 2.73
- *
- 195E-5.36 A 5-19 Xl = 2πFL, Xl = 452.1|Q = R/X, Q = 100/452.1
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 7.125 MHz, the inductance is 10.1
- microhenrys and the resistance is 100 ohms?
-
- A. 0.221
- B. 4.52
- C. 0.00452
- D. 22.1
- *
- 196E-5.37 B 5-19 Xl = 2πFL, Xl = 564.1|Q = R/X, Q = 22000/564.1
- What is the Q of the circuit in Figure 4AE-5-3 when the
- resonant frequency is 7.125 MHz, the inductance is 12.6
- microhenrys and the resistance is 22,000 ohms?
-
- A. 22.1
- B. 39
- C. 25.6
- D. 0.0256
- *
- 197E-5.38 B 5-19 Xl = 2πFL, Xl = 68.32|Q = R/X, Q = 2200/68.32
- What is the Q of the circuit in Figure 4AE-5-3 when the resonant
- frequency is 3.625 MHz, the inductance is 3 microhenrys and the
- resistance is 2,200 ohms?
-
- A. 0.031
- B. 32.2
- C. 31.1
- D. 25.6
- *
- 198E-5.39 D 5-19 Xl = 2πFL, Xl = 956.6|Q = R/X, Q= 956.6/220
- What is the Q of the circuit in Figure 4AE-5-3 when the resonant
- frequency is 3.625 MHz, the inductance is 42 microhenrys and the
- resistance is 220 ohms?
-
- A. 23
- B. 0.00435
- C. 4.35
- D. 0.23
- *
- 199E-5.40 A 5-19 Xl = 2πFL, Xl = 979.4|Q = R/X, Q=1800/979.4
- What is the Q of the circuit in Figure 4AE-5-3 when the resonant
- frequency is 3.625 MHz, the inductance is 43 microhenrys and the
- resistance is 1,800 ohms?
-
- A. 1.84
- B. 0.543
- C. 54.3
- D. 23
- *
- 200E-6.1 A 5-11 Z = R +jXl -jXc, Z = 100 +j100 -j25|Z=100 +j75, +j Leading, Θ = ATAN(X/R)|Θ = ATAN(+75/100), Θ = +36.9°
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 25
- ohms, R is 100 ohms, and Xl is 100 ohms?
-
- A. 36.9 degrees with the voltage leading the current
- B. 53.1 degrees with the voltage lagging the current
- C. 36.9 degrees with the voltage lagging the current
- D. 53.1 degrees with the voltage leading the current
- *
- 201E-6.2 B 5-11 Z = R +jXl -jXc, Z = 100 +j50 -j25|Z=100 +j25, +j Leading, Θ = ATAN(X/R)|Θ = ATAN(+25/100), Θ = +14.0°
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 25
- ohms, R is 100 ohms, and Xl is 50 ohms?
-
- A. 14 degrees with the voltage lagging the current
- B. 14 degrees with the voltage leading the current
- C. 76 degrees with the voltage lagging the current
- D. 76 degrees with the voltage leading the current
- *
- 202E-6.3 C 5-11 Z = R +jXl -jXc, Z = 1000 +j250 -j500|Z=1000 -j250, -j lagging, Θ=ATAN(X/R)|Θ = ATAN(-250/1000), Θ = -14.0°
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 500
- ohms, R is 1000 ohms, and Xl is 250 ohms?
-
- A. 68.2 degrees with the voltage leading the current
- B. 14.1 degrees with the voltage leading the current
- C. 14.1 degrees with the voltage lagging the current
- D. 68.2 degrees with the voltage lagging the current
- *
- 203E-6.4 B 5-11 Z = R +jXl -jXc, Z = 100 +j100 -j75|Z=100 +j25, Θ=ATAN(X/R), Θ = ATAN(.25)|Θ = +14°, Note positive angle, leading
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 75
- ohms, R is 100 ohms, and Xl is 100 ohms?
-
- A. 76 degrees with the voltage leading the current
- B. 14 degrees with the voltage leading the current
- C. 14 degrees with the voltage lagging the current
- D. 76 degrees with the voltage lagging the current
- *
- 204E-6.5 D 5-11 Z = R +jXl -jXc, Z = 100 +j25 -j50|Z=100-j25, Θ=ATAN(X/R), Θ = ATAN(-.25)|Θ = -14°, Note negative angle, lagging
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 50
- ohms, R is 100 ohms, and Xl is 25 ohms?
-
- A. 76 degrees with the voltage lagging the current
- B. 14 degrees with the voltage leading the current
- C. 76 degrees with the voltage leading the current
- D. 14 degrees with the voltage lagging the current
- *
- 205E-6.6 B 5-11 Z = R +jXl -jXc, Z = 100 +j50 -j75|Z=100-j25, Θ=ATAN(X/R), Θ = ATAN(-.25)|Θ = -14°, Note negative angle, lagging
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 75
- ohms, R is 100 ohms, and Xl is 50 ohms?
-
- A. 76 degrees with the voltage lagging the current
- B. 14 degrees with the voltage lagging the current
- C. 14 degrees with the voltage leading the current
- D. 76 degrees with the voltage leading the current
- *
- 206E-6.7 A 5-11 Z = R +jXl -jXc, Z = 100 +j75 -j100|Z=100-j25, Θ=ATAN(X/R), Θ = ATAN(-.25)|Θ = -14°, Note negative angle, lagging
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 100
- ohms, R is 100 ohms, and Xl is 75 ohms?
-
- A. 14 degrees with the voltage lagging the current
- B. 14 degrees with the voltage leading the current
- C. 76 degrees with the voltage leading the current
- D. 76 degrees with the voltage lagging the current
- *
- 207E-6.8 D 5-11 Z = R +jXl -jXc, Z = 1000 +j500 -j250|Z=1000+j250, +j leading/positive angle|Θ=ATAN(250/1000), Θ=ATAN(.25), Θ = 14°
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 250
- ohms, R is 1000 ohms, and Xl is 500 ohms?
-
- A. 81.47 degrees with the voltage lagging the current
- B. 81.47 degrees with the voltage leading the current
- C. 14.04 degrees with the voltage lagging the current
- D. 14.04 degrees with the voltage leading the current
- *
- 208E-6.9 D 5-11 Z = R +jXl -jXc, Z = 100 +j75 -j50|Z=100 +j25, Θ=ATAN(X/R), Θ = ATAN(.25)|Θ = +14°, Note positive angle, leading
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 50
- ohms, R is 100 ohms, and Xl is 75 ohms?
-
- A. 76 degrees with the voltage leading the current
- B. 76 degrees with the voltage lagging the current
- C. 14 degrees with the voltage lagging the current
- D. 14 degrees with the voltage leading the current
- *
- 209E-6.10 C 5-11 Z = R +jXl -jXc, Z = 100 +j25 -j100|Z=100-j75, -j Lagging, Θ = ATAN(X/R)|Θ = ATAN(-75/100), Θ = -36.9°
- What is the phase angle between the voltage across and the
- current through the circuit in Figure 4AE-6, when Xc is 100
- ohms, R is 100 ohms, and Xl is 25 ohms?
-
- A. 36.9 degrees with the voltage leading the current
- B. 53.1 degrees with the voltage lagging the current
- C. 36.9 degrees with the voltage lagging the current
- D. 53.1 degrees with the voltage leading the current
- *
- 210E-7.1 A 5-21 Phase angle is greater that zero
- Why would the rate at which electrical energy is used in a
- circuit be less than the product of the magnitudes of the AC
- voltage and current?
-
- A. Because there is a phase angle that is greater than zero
- between the current and voltage
- B. Because there are only resistances in the circuit
- C. Because there are no reactances in the circuit
- D. Because there is a phase angle that is equal to zero
- between the current and voltage
- *
- 211E-7.2 A 5-22 P=V*I*COS(Θ) Where COS(Θ)|is the power factor
- In a circuit where the AC voltage and current are out of phase,
- how can the true power be determined?
-
- A. By multiplying the apparent power times the power factor
- B. By subtracting the apparent power from the power factor
- C. By dividing the apparent power by the power factor
- D. By multiplying the RMS voltage times the RMS current
- *
- 212E-7.3 C 5-23 COS(60°)
- What does the power factor equal in an R-L circuit having a
- 60 degree phase angle between the voltage and the current?
-
- A. 1.414
- B. 0.866
- C. 0.5
- D. 1.73
- *
- 213E-7.4 D 5-23 COS(45°)
- What does the power factor equal in an R-L circuit having a
- 45 degree phase angle between the voltage and the current?
-
- A. 0.866
- B. 1.0
- C. 0.5
- D. 0.707
- *
- 214E-7.5 C 5-23 COS(30°)
- What does the power factor equal in an R-L circuit having a
- 30 degree phase angle between the voltage and the current?
-
- A. 1. 73
- B. 0.5
- C. 0.866
- D. 0.577
- *
- 215E-7.6 B 5-22 P = V*I*COS(Θ)|COS(Θ) = 0.2 |P = 100*4*0.2
- How many watts are being consumed in a circuit having a power
- factor of 0.2 when the input is 100-Vac and 4-amperes is being
- drawn?
-
- A. 400 watts
- B. 80 watts
- C. 2000 watts
- D. 50 watts
- *
- 216E-7.7 D 5-22 P = V*I*COS(Θ)|COS(Θ) = 0.6 |P = 200*5*0.6
- How many watts are being consumed in a circuit having a power
- factor of 0.6 when the input is 200-Vac and 5-amperes is being
- drawn?
-
- A. 200 watts
- B. 1000 watts
- C. 1600 watts
- D. 600 watts
- *
- 217E-8.1 B 5-24 Add dBs, -4-3+6 = -1 dB|dBs to N, N = 10(-1/10)|ERP = 50*N, ERP = 50*.794
- What is the effective radiated power of a station in repeater
- operation with 50 watts transmitter power output, 4 dB feedline
- loss, 3 dB duplexer and circulator loss, and 6 dB antenna gain?
-
- A. 158 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 39.7 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 251 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 69.9 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 218E-8.2 C 5-24 -5-4+7=-2 dB, Net loss|Must be smaller that 50
- What is the effective radiated power of a station in repeater
- operation with 50 watts transmitter power output, 5 dB feedline
- loss, 4 dB duplexer and circulator loss, and 7 dB antenna gain?
-
- A. 300 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 315 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 31.5 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 69.9 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 219E-8.3 D 5-24 Add dBs, -4-3+10 = 3 dB|dBs to N, N = 10(3/10)|ERP = 50*N, ERP = 75*2.0
- What is the effective radiated power of a station in repeater
- operation with 75 watts transmitter power output, 4 dB feedline
- loss, 3 dB duplexer and circulator loss, and 10 dB antenna gain?
-
- A. 600 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 75 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 18.75 watts, assuming the antenna gain is referenced to a
- half-wave dipole
- D. 150 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 220E-8.4 A 5-24 -5-4+6 = -3 dB, Net loss|-3 dB is half power point
- What is the effective radiated power of a station in repeater
- operation with 75 watts transmitter power output, 5 dB feedline
- loss, 4 dB duplexer and circulator loss, and 6 dB antenna gain?
-
- A. 37.6 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 237 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 150 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 23.7 wafts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 221E-8.5 D 5-24 Add dBs, -4-3+7 = 0 dB|ERP = output power
- What is the effective radiated power of a station in repeater
- operation with 100 watts transmitter power output, 4 dB feedline
- loss, 3 dB duplexer and circulator loss, and 7 dB antenna gain?
-
- A. 631 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 400 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 25 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 100 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 222E-8.6 B 5-24 -5-4+10 = +1 dB|Slight increase|Try 126 watts
- What is the effective radiated power of a station in repeater
- operation with 100 watts transmitter power output, 5 dB feedline
- loss, 4 dB duplexer and circulator loss, and 10 dB antenna gain?
-
- A. 800 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 126 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 12.5 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 1260 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 223E-8.7 C 5-24 -5-4+6 = -3 dB or half power
- What is the effective radiated power of a station in repeater
- operation with 120 watts transmitter power output, 5 dB feedline
- loss, 4 dB duplexer and circulator loss, and 6 dB antenna gain?
-
- A. 601 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 240 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 60 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 379 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 224E-8.8 D 5-24 Add dBs, -4-3+7 = 0 dB|ERP = output power
- What is the effective radiated power of a station in repeater
- operation with 150 watts transmitter power output, 4 dB feedline
- loss, 3 dB duplexer and circulator loss, and 7 dB antenna gain?
-
- A. 946 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 37.5 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 600 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 150 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 225E-8.9 A 5-24 Add dBs, -4-4+10 = + 2 dB|dBs to N, N = 10(2/10)|ERP = 200*N, ERP = 200*1.58
- What is the effective radiated power of a station in repeater
- operation with 200 watts transmitter power output, 4 dB feedline
- loss, 4 dB duplexer and circulator loss, and 10 dB antenna gain?
-
- A. 317 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 2000 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 126 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 260 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 226E-8.10 D 5-24 -4-3+6 = -1 dB, Slight Loss|Try 159 Watts
- What is the effective radiated power of a station in repeater
- operation with 200 watts transmitter power output, 4 dB feedline
- loss, 3 dB duplexer and circulator loss, and 6 dB antenna gain?
-
- A. 252 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- B. 63.2 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- C. 632 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- D. 159 watts, assuming the antenna gain is referenced to a half-
- wave dipole
- *
- 227E-9.1 B 5-24 Rt = R1/2 (Parallel equals)|V2 = V1/2 (Divider equal)
- In Figure 4AE-9, what values of V2 and R3 result in the same
- voltage and current characteristics as when V1 is 8-vo1ts, R1
- is 8 kilohms, and R2 is 8 kilohms?
-
- A. R3 = 4 kilohms and V2 = 8 volts
- B. R3 = 4 kilohms and V2 = 4 volts
- C. R3 = 16 kilohms and V2 = 8 volts
- D. R3 = 16 kilohms and V2 = 4 volts
- *
-